int posix_memalign(void **memptr, size_t alignment,
The posix_memalign() function shall allocate size bytes aligned on a boundary specified by alignment, and shall return a pointer to the allocated memory in memptr. The value of alignment shall be a multiple of sizeof( void *), that is also a power of two. Upon successful completion, the value pointed to by memptr shall be a multiple of alignment.
The free() function shall deallocate memory that has previously been allocated by posix_memalign().
Upon successful completion, posix_memalign() shall return zero; otherwise, an error number shall be returned to indicate the error.
The posix_memalign() function shall fail if:
- The value of the alignment parameter is not a power of two multiple of sizeof( void *).
There is insufficient memory available with the requested alignment.
The following sections are informative.
The posix_memalign() function is part of the Advisory Information option and need not be provided on all implementations.
COPYRIGHTPortions of this text are reprinted and reproduced in electronic form from IEEE Std 1003.1, 2003 Edition, Standard for Information Technology -- Portable Operating System Interface (POSIX), The Open Group Base Specifications Issue 6, Copyright (C) 2001-2003 by the Institute of Electrical and Electronics Engineers, Inc and The Open Group. In the event of any discrepancy between this version and the original IEEE and The Open Group Standard, the original IEEE and The Open Group Standard is the referee document. The original Standard can be obtained online at http://www.opengroup.org/unix/online.html .