SYNOPSIS

SUBROUTINE CLATZM(

SIDE, M, N, V, INCV, TAU, C1, C2, LDC, WORK )

    

CHARACTER SIDE

    

INTEGER INCV, LDC, M, N

    

COMPLEX TAU

    

COMPLEX C1( LDC, * ), C2( LDC, * ), V( * ), WORK( * )

PURPOSE

This routine is deprecated and has been replaced by routine CUNMRZ. CLATZM applies a Householder matrix generated by CTZRQF to a matrix. Let P = I - tau*u*u', u = ( 1 ),

                            ( v )
where v is an (m-1) vector if SIDE = 'L', or a (n-1) vector if SIDE = 'R'.
If SIDE equals 'L', let

       C = [ C1 ] 1

           [ C2 ] m-1

             n
Then C is overwritten by P*C.
If SIDE equals 'R', let

       C = [ C1, C2 ] m

              1  n-1
Then C is overwritten by C*P.

ARGUMENTS

SIDE (input) CHARACTER*1

= 'L': form P * C
= 'R': form C * P

M (input) INTEGER

The number of rows of the matrix C.

N (input) INTEGER

The number of columns of the matrix C.

V (input) COMPLEX array, dimension

(1 + (M-1)*abs(INCV)) if SIDE = 'L' (1 + (N-1)*abs(INCV)) if SIDE = 'R' The vector v in the representation of P. V is not used if TAU = 0.

INCV (input) INTEGER

The increment between elements of v. INCV <> 0

TAU (input) COMPLEX

The value tau in the representation of P.

C1 (input/output) COMPLEX array, dimension

(LDC,N) if SIDE = 'L' (M,1) if SIDE = 'R' On entry, the n-vector C1 if SIDE = 'L', or the m-vector C1 if SIDE = 'R'. On exit, the first row of P*C if SIDE = 'L', or the first column of C*P if SIDE = 'R'.

C2 (input/output) COMPLEX array, dimension

(LDC, N) if SIDE = 'L' (LDC, N-1) if SIDE = 'R' On entry, the (m - 1) x n matrix C2 if SIDE = 'L', or the m x (n - 1) matrix C2 if SIDE = 'R'. On exit, rows 2:m of P*C if SIDE = 'L', or columns 2:m of C*P if SIDE = 'R'.

LDC (input) INTEGER

The leading dimension of the arrays C1 and C2. LDC >= max(1,M).

WORK (workspace) COMPLEX array, dimension

(N) if SIDE = 'L' (M) if SIDE = 'R'