eX_subscribe.h(3) eXosip subscribe request API

SYNOPSIS


#include <osipparser2/osip_parser.h>
#include <time.h>

Enumerations


enum eXosip_ss { EXOSIP_SUBCRSTATE_UNKNOWN, EXOSIP_SUBCRSTATE_PENDING, EXOSIP_SUBCRSTATE_ACTIVE, EXOSIP_SUBCRSTATE_TERMINATED }

enum eXosip_ss_reason { DEACTIVATED, PROBATION, REJECTED, TIMEOUT, GIVEUP, NORESOURCE }

enum eXosip_ss_status { EXOSIP_NOTIFY_UNKNOWN, EXOSIP_NOTIFY_PENDING, EXOSIP_NOTIFY_ONLINE, EXOSIP_NOTIFY_BUSY, EXOSIP_NOTIFY_BERIGHTBACK, EXOSIP_NOTIFY_AWAY, EXOSIP_NOTIFY_ONTHEPHONE, EXOSIP_NOTIFY_OUTTOLUNCH, EXOSIP_NOTIFY_CLOSED }

Functions


int eXosip_subscribe_build_initial_request (struct eXosip_t *excontext, osip_message_t **subscribe, const char *to, const char *from, const char *route, const char *event, int expires)

int eXosip_subscribe_send_initial_request (struct eXosip_t *excontext, osip_message_t *subscribe)

int eXosip_subscribe_build_refresh_request (struct eXosip_t *excontext, int did, osip_message_t **sub)

int eXosip_subscribe_send_refresh_request (struct eXosip_t *excontext, int did, osip_message_t *sub)

int eXosip_subscribe_remove (struct eXosip_t *excontext, int did)

int eXosip_insubscription_build_answer (struct eXosip_t *excontext, int tid, int status, osip_message_t **answer)

int eXosip_insubscription_send_answer (struct eXosip_t *excontext, int tid, int status, osip_message_t *answer)

int eXosip_insubscription_build_request (struct eXosip_t *excontext, int did, const char *method, osip_message_t **request)

int eXosip_insubscription_build_notify (struct eXosip_t *excontext, int did, int subscription_status, int subscription_reason, osip_message_t **request)

int eXosip_insubscription_send_request (struct eXosip_t *excontext, int did, osip_message_t *request)

int eXosip_insubscription_remove (struct eXosip_t *excontext, int did)

Detailed Description

eXosip subscribe request API

This file provide the API needed to control SUBSCRIBE requests. You can use it to:

  • build SUBSCRIBE requests.
  • send SUBSCRIBE requests.
  • build SUBSCRIBE answers.
  • send SUBSCRIBE answers.

Author

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