int im_divide(in1, in2, out)
IMAGE *in1, *in2, *out;
DESCRIPTIONim_divide(3) divides two images. The result is float except if one (or both) input is double. In the latter case the result is double. If either input is complex, the result is complex. If either input is double complex, the output is double complex.
Input images in1 and in2 should have the same channels and the same sizes, however they can be of different types.
For complex input pels (x1,y1) and (x2,y2),
((x1*x2 + y1*y2)/(x2*x2 + y2*y2), (y1*x2 - x1*y2)/(x2*x2 + y2*y2)).
BUGSThe function does not check the result for over/underflow.
RETURN VALUEThe function returns 0 on success and -1 on error.
COPYRIGHTNational Gallery, 1995